Given below are two statements:
Statement (I): In the Lanthanoids, the formation of Ce⁺⁴ is favoured by its noble gas configuration.
Statement (II): Ce⁺⁴ is a strong oxidant reverting to the common +3 state.
In the light of the above statements, choose the most appropriate answer from the options given below:
Statement (I): In the Lanthanoids, the formation of Ce⁺⁴ is favoured by its noble gas configuration.
Statement (II): Ce⁺⁴ is a strong oxidant reverting to the common +3 state.
In the light of the above statements, choose the most appropriate answer from the options given below:
- (A)Statement I is false but Statement II is true
- (B)Both Statement I and Statement II are true✓ Correct
- (C)Statement I is true but Statement II is false
- (D)Both Statement I and Statement II are false
Answer: (B)
Solution
Cerium has the configuration . Losing all four of these electrons gives , a stable noble-gas configuration, which is why the +4 state is accessible for cerium unlike most other lanthanoids — Statement I is true.
Despite this stability, the couple has a large positive reduction potential ( V), so readily accepts an electron and is reduced back to the common state, acting as a strong oxidant in the process — Statement II is also true.
Despite this stability, the couple has a large positive reduction potential ( V), so readily accepts an electron and is reduced back to the common state, acting as a strong oxidant in the process — Statement II is also true.
JEE Main · 2024 · 27 Jan 2024 · Shift 2 · Single correct option