A light unstretchable string passing over a smooth light pulley connects two blocks of masses $\mathrm{m}_{1}$ and $\mathrm{m}_{2}$. If the acceleration of the system is $\frac{\mathrm{g}}{8}$, then the ratio of the masses $\frac{\mathrm{m}_{2}}{\mathrm{~m}_{1}}$ is:

JEE Main · 2024 · 09 Apr 2024 · Shift 1 · Laws of Motion

A light unstretchable string passing over a smooth light pulley connects two blocks of masses

m_{1}

and

m_{2}

. If the acceleration of the system is

\frac{g}{8}

, then the ratio of the masses

\frac{m _{2}}{m _{1}}

is:

(A)9:7✓ Correct
(B)4:3
(C)5:3
(D)8:1

Answer: (A)

Solution

For an Atwood system

a = \frac{m _{2} - m _{1}}{m _{2} + m _{1}} g = \frac{g}{8}

, so

\frac{m _{2} - m _{1}}{m _{2} + m _{1}} = \frac{1}{8} \Rightarrow \frac{m _{2}}{m _{1}} = \frac{9}{7}

. Option (1).

JEE Main · 2024 · 09 Apr 2024 · Shift 1 · Single correct option

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