JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Laws of Motion

A 2 kg brick begins to slide over a surface which is inclined at an angle of

4 5^{\circ}

with respect to horizontal axis. The co-efficient of static friction between their surfaces is :

(A)1✓ Correct
(B) $\frac{1}{3}$
(C)0.5
(D)1.7

Answer: (A)

Solution

At the point the block is about to slide, static friction is at its maximum and the block is in equilibrium along the incline:

m g sin θ = f_{s} = μ_{s} N = μ_{s} m g cos θ

μ_{s} = tan θ = tan 4 5^{\circ} = 1

JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Single correct option

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