0.1 M solution of KI reacts with excess of and solution. According to equation
Identify the correct statements :
(A) 200 mL of KI solution reacts with 0.004 mol of
(B) 200 mL of KI solution reacts with 0.006 mol of
(C) 0.5 L of KI solution produced 0.005 mol of
(D) Equivalent weight of is equal to
Choose the correct answer from the options given below:
Identify the correct statements :
(A) 200 mL of KI solution reacts with 0.004 mol of
(B) 200 mL of KI solution reacts with 0.006 mol of
(C) 0.5 L of KI solution produced 0.005 mol of
(D) Equivalent weight of is equal to
Choose the correct answer from the options given below:
- (A)(A) and (D) only✓ Correct
- (B)(B) and (C) only
- (C)(A) and (B) only
- (D)(C) and (D) only
Answer: (A)
Solution
The balanced equation fixes the stoichiometry. 200 mL of 0.1 M KI gives mol. Since 5 mol reacts with 1 mol , the consumed is mol — (A) is correct. The same 0.02 mol requires mol , which needs mol (each supplies 2 ), not 0.006 mol — (B) is false. For 0.5 L of 0.1 M KI, mol, giving mol, not 0.005 mol — (C) is false. In this reaction iodine in goes from +5 to 0 in , a 5-electron change per iodine atom, so the equivalent weight of is — (D) is correct. Statements (A) and (D) alone are true.
JEE Main · 2025 · 29 Jan 2025 · Shift 2 · Single correct option