The amphoteric oxide among $\mathrm{V}_{2} \mathrm{O}_{3}, \mathrm{~V}_{2} \mathrm{O}_{4}$ and $\mathrm{V}_{2} \mathrm{O}_{5}$ upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

JEE Main · 2025 · 28 Jan 2025 · Shift 2 · d and f Block Elements

The amphoteric oxide among

V_{2} O_{3}, V_{2} O_{4}

and

V_{2} O_{5}

upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

Answer: (C)

Among

V_{2} O_{3}

V_{2} O_{4}

and

V_{2} O_{5}

, only

V_{2} O_{5}

is amphoteric — it dissolves in alkali to give the vanadate ion,

V O_{4}^{3 -}

. Assigning oxidation states in

V O_{4}^{3 -}

with oxygen at

- 2

x + 4 (- 2) = - 3 \Rightarrow x = + 5

. Vanadium sits in the +5 oxidation state in this anion.

JEE Main · 2025 · 28 Jan 2025 · Shift 2 · Single correct option