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JEE Main · 2024 · 05 Apr 2024 · Shift 2 · General Organic Chemistry

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Match List - I with List - II.

List - I (Pair of Compounds)
(A) n-propanol and Isopropanol
(B) Methoxypropane and ethoxyethane
(C) Propanone and propanal
(D) Neopentane and Isopentane

List - II (Isomerism)
(I) Metamerism
(II) Chain Isomerism
(III) Position Isomerism
(IV) Functional Isomerism

Answer: A → III, B → I, C → IV, D → II

Solution

n-Propanol and isopropanol are alcohols differing only in the position of the group on the same carbon skeleton — position isomers — (A)–(III).
Methoxypropane and ethoxyethane are both ethers of formula but split differently about the oxygen atom — metamers — (B)–(I).
Propanone and propanal are both but belong to different functional classes (ketone vs. aldehyde) — functional isomers — (C)–(IV).
Neopentane and isopentane are both , differing only in the branching of the carbon chain — chain isomers — (D)–(II).
Hence A–III, B–I, C–IV, D–II.

JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Match the columns

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