JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Chemical Thermodynamics

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Three moles of an ideal gas are compressed isothermally from 60 L to 20 L using constant pressure of 5 atm. Heat exchange Q for the compression is - _____ Lit. atm.

Answer: 200

Solution

Isothermal process for an ideal gas:

Δ U = 0

. The compression is irreversible, against a constant external pressure of 5 atm, from

V_{1} = 60 L

V_{2} = 20 L

Q = - W = - [- P_{e x t} (V_{2} - V_{1})] = P_{e x t} (V_{2} - V_{1}) = 5 (20 - 60) = - 200 L atm

Since the question already states the answer as "

-___

L atm", the blank is 200.

JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Integer answer

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