The product formed in the first step of the reaction of
with excess Mg/Et2O(Et=C2H5) is :
(A)(see structure)
(B)(see structure)
(C)(see structure)✓ Correct
(D)(see structure)
Answer: (C)
Solution
When a dibromide reacts with excess magnesium in dry ether (Mg/EtX2O), a Grignard reagent is formed at each bromine site. In the first step, one of the bromine atoms is replaced by MgBr to form a Grignard reagent.
For the given compound (2,4-dibromopentane), the first step involves the formation of a Grignard reagent at one of the bromine positions while the other bromine remains unreacted initially.
The product of the first step is: CHX3CH(MgBr)CHX2CH(Br)CHX3
This corresponds to option (3), which shows the structure with one MgBr group and one Br group still attached to the carbon chain.
JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Single correct option