Let a circle C of radius 1 and closer to the origin be such that the lines passing through the point (3,2) and parallel to the coordinate axes touch it. Then the shortest distance of the circle C from the point (5,5) is:
(A)5
(B)4✓ Correct
(C)42
(D)22
Answer: (B)
Solution
The lines x=3,y=2 through (3,2) parallel to the axes are tangent to a circle of radius 1; the centre nearer the origin is at (3−1,2−1)=(2,1), giving circle (x−2)2+(y−1)2=1. Distance from centre to (5,5): (5−2)2+(5−1)2=9+16=5. Shortest distance from the circle =5−1=4.
JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Single correct option