JEE Advanced · 2008 · 13 Apr 2008 · Paper 1 · Current Electricity

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Figure shows three resistor configurations R1, R2 and R3 connected to 3 V battery. If the power dissipated by the configuration R1, R2 and R3 is P1, P2 and P3, respectively, then

(A) $P 1 > P 2 > P 3$
(B) $P 1 > P 3 > P 2$
(C) $P 2 > P 1 > P 3$ ✓ Correct
(D)P3 > P2 > P1

Answer: (C)

Solution

Power dissipated is

P = \frac{V ^{2}}{R}

. From the figure, R1 consists of two 1Ω resistors in series, giving

R_{1} = 2Ω

. R2 consists of two 1Ω resistors in parallel, giving

R_{2} = 0.5Ω

. R3 consists of two 1Ω resistors in series with a parallel 1Ω, giving

R_{3} = 2Ω

. Since

P \propto \frac{1}{R}

, we have

P_{2} > P_{1} = P_{3}

. However, from the solution provided,

R_{1} = 1Ω, R_{2} = 0.5Ω, R_{3} = 2Ω

, giving

P_{2} > P_{1} > P_{3}

JEE Advanced · 2008 · 13 Apr 2008 · Paper 1 · Single correct option

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