Photoelectric effect experiments are performed using three different metal plates p,q and r having work functions ϕp=2.0eV,ϕq=2.5eV and ϕr=3.0eV, respectively. A light beam containing wavelengths of 550nm,450nm and 350 nm with equal intensities illuminates each of the plates. The correct I-V graph for the experiment is [Take hc=1240eVnm ]
(A)(see structure)✓ Correct
(B)(see structure)
(C)(see structure)
(D)(see structure)
Answer: (A)
Solution
The stopping potential is given by V0=e1[λhc−ϕ]. For the three plates:
Vp=5501240−2.0=0.2545 V
Vq=4501240−2.5=0.255 V
Vr=3501240−3.0=0.5428 V
Since the intensities are equal, the photocurrent is proportional to the number of photons, which is proportional to wavelength. Thus ip:iq:ir=λp:λq:λr=550:450:350. Graph (A) correctly shows these stopping potentials and relative photocurrents.
JEE Advanced · 2009 · 12 Apr 2009 · Paper 2 · Single correct option