Consider a hydrogen atom with and denoting the velocity, orbital radius and kinetic energy of the electron in the orbit, respectively. The electron undergoes a transition from the orbit, emitting radiation corresponding to the Lyman series. Considering to be the Planck's constant and the permittivity of the free space, the correct statement(s) is/are:
- (A)Magnitude of change in kinetic energy of electron can be expressed as .✓ Correct
- (B)Magnitude of change in de Broglie wavelength of the electron can be expressed as .
- (C)Frequency of the radiation emitted can be expressed as .✓ Correct
- (D)Magnitude of change in total energy of the electron can be expressed as .
Answer: (A), (C)
Solution
For hydrogen atom: and .
(A) ✓
(B) The expression gives ✗
(C) Energy of photon: , so ✓
(D) The expression equals , not the total energy change ✗
(A) ✓
(B) The expression gives ✗
(C) Energy of photon: , so ✓
(D) The expression equals , not the total energy change ✗
JEE Advanced · 2026 · 17 May 2026 · Paper 1 · One or more correct options