The difference in the oxidation numbers of the two types of sulphur atoms in is
Answer: 5
Solution
is sodium tetrathionate. Its structure shows two types of sulfur atoms:
Difference = 5 - 0 = 5
- Two terminal sulfur atoms bonded to oxygen: oxidation state = +5
- Two central sulfur atoms in S-S bonds: oxidation state = 0
Difference = 5 - 0 = 5
JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Integer answer