JEE Advanced · 2011 · 10 Apr 2011 · Paper 2 · Chemical Thermodynamics

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Match the transformations in column I with appropriate options in column II
Column IColumn II
(A) (p) phase transition
(B) (q) allotropic change
(C) (r) is positive
(D) (s) is positive
(t) is negative

Answer: A → I, A → III, A → IV, B → III, B → IV, C → V, D → I, D → II, D → V

Solution

(A) Sublimation of CO₂: Solid to gas is a phase transition (p), requires heat input so ΔH > 0 (r), and increases disorder so ΔS > 0 (s). Matches: p, r, s

(B) Decomposition of CaCO₃: Endothermic reaction so ΔH > 0 (r), produces gas from solid increasing entropy so ΔS > 0 (s). Matches: r, s

(C) Formation of H₂ from atoms: Bond formation releases energy (exothermic), and two separate atoms combining into one molecule decreases entropy, so ΔS < 0 (t). Matches: t

(D) White phosphorus to red phosphorus: Allotropic change (q), also a phase transition in solid state (p), exothermic (more stable form) and decreases disorder so ΔS < 0 (t). Matches: p, q, t

JEE Advanced · 2011 · 10 Apr 2011 · Paper 2 · Match the columns

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