Two batteries of different emfs and different internal resistances are connected as shown. The voltage across AB in volts is
Answer: 5
Solution
Current in the circuit: i=36−3=1 A (flowing from the 6V battery). Applying Kirchhoff's voltage law from A to B through the 6V battery: VA−6+1(1)−VB=0, giving VA−VB=5 V.