Question

Paragraph for Questions 11 and 12

The mass of a nucleus ${}_{Z}^{A} X$ is less than the sum of the masses of ( $A-Z$ ) number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m_{1}$ and $m_{2}$ only if $(m_{1}+m_{2})<M$. Also two light nuclei of masses $m_{3}$ and $m_{4}$ can undergo complete fusion and form a heavy nucleus of mass $M^{\prime}$ only if $(m_{3}+m_{4})>M^{\prime}$. The masses of some neutral atoms are given in the table below:

| ${}_{1}^{1} H$ | 1.007825 u | ${}_{1}^{2} H$ | 2.014102 u | ${}_{1}^{3} H$ | 3.016050 u | ${}_{2}^{4} \mathrm{He}$ | 4.002603 u |
| --- | --- | --- | --- | --- | --- | --- | --- |
| ${}_{3}^{6} Li$ | 6.015123 u | ${}_{3}^{7} \mathrm{Li}$ | 7.016004 u | ${}_{30}^{70} \mathrm{Zn}$ | 69.925325 u | ${}_{34}^{82} \mathrm{Se}$ | 81.916709 u |
| ${}_{64}^{152} Gd$ | 151.919803 u | ${}_{82}^{206} \mathrm{~Pb}$ | 205.974455 u | ${}_{83}^{209} \mathrm{Bi}$ | 208.980388 u | ${}_{84}^{210} \mathrm{Po}$ | 209.982876 u |

$(1 u=932 MeV / c^{2})$

The kinetic energy (in keV ) of the alpha particle, when the nucleus ${}_{84}^{210} \mathrm{Po}$ at rest undergoes alpha decay, is

Accepted Answer

(A) 5319

Answer

(B) 5422

Answer

(C) 5707

Answer

(D) 5818

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Modern Physics

Solution

More JEE Advanced questions on Modern Physics

$_{1}^{1} H$	1.007825 u	$_{1}^{2} H$	2.014102 u	$_{1}^{3} H$	3.016050 u	$_{2}^{4} He$	4.002603 u
$_{3}^{6} L i$	6.015123 u	$_{3}^{7} Li$	7.016004 u	$_{30}^{70} Zn$	69.925325 u	$_{34}^{82} Se$	81.916709 u
$_{64}^{152} G d$	151.919803 u	$_{82}^{206} Pb$	205.974455 u	$_{83}^{209} Bi$	208.980388 u	$_{84}^{210} Po$	209.982876 u