The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists: | List I | | | --- | --- | | P. | $\mathrm{PbO}_{2}+\mathrm{H}_{2}\mathrm{SO}_{4} \xrightarrow{?} \mathrm{PbSO}_{4}+\mathrm{O}_{2}+$ other product | | Q. | $\mathrm{Na}_{2}\mathrm{~S}_{2}\mathrm{O}_{3}+\mathrm{H}_{2}\mathrm{O} \xrightarrow{?} \mathrm{NaHSO}_{4}+$ other product | | R. | $\mathrm{N}_{2}\mathrm{H}_{4} \xrightarrow{?} \mathrm{~N}_{2}+$ other product | | S. | $\mathrm{XeF}_{2} \xrightarrow{?} \mathrm{Xe}+$ other product | | List II | | | --- | --- | | 1. | NO | | 2. | $I_{2}$ | | 3. | Warm | | 4. | $\mathrm{Cl}_{2}$ |

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Redox Reactions and Electrochemistry

The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists:

List I
P.	$PbO_{2} + H_{2} SO_{4} ? PbSO_{4} + O_{2} +$ other product
Q.	$Na_{2} S_{2} O_{3} + H_{2} O ? NaHSO_{4} +$ other product
R.	$N_{2} H_{4} ? N_{2} +$ other product
S.	$XeF_{2} ? Xe +$ other product

List II
1.	NO
2.	$I_{2}$
3.	Warm
4.	$Cl_{2}$

(A)P-4, Q-2, R-3, S-1
(B)P-3, Q-2, R-1, S-4
(C)P-1, Q-4, R-2, S-3
(D)P-3, Q-4, R-2, S-1✓ Correct

Answer: (D)

Solution

Matching the reactions:

P:

PbO_{2} + H_{2} SO_{4} Heat PbSO_{4} + O_{2} + H_{2} O

→ Warm (3)

Q:

Na_{2} S_{2} O_{3} + H_{2} O Cl_{2} NaHSO_{4} + S + HCl

→

Cl_{2}

(4)

R:

N_{2} H_{4} I_{2} N_{2} + HI

→

I_{2}

(2)

S:

XeF_{2} NO Xe + NO_{2} F

→ NO (1)

Code: P-3, Q-4, R-2, S-1

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Single correct option

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JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Redox Reactions and Electrochemistry

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