JEE Advanced · 2015 · 24 May 2015 · Paper 2 · p-Block Elements

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Three moles of B₂H₆ are completely reacted with methanol. The number of moles of boron containing product formed is

Answer: 6

Solution

The reaction is:

B₂H₆ + 6CH₃OH → 2B(OCH₃)₃ + 6H₂

From 1 mole of B₂H₆, 2 moles of B(OCH₃)₃ are formed.

From 3 moles of B₂H₆, moles of boron-containing product = 3 × 2 = 6 moles.

JEE Advanced · 2015 · 24 May 2015 · Paper 2 · Integer answer

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