Correct statement(s) about the compounds $\mathbf{P}$, $\mathbf{Q}$ and $\mathbf{R}$ is(are) $\text{Xe}(g) + \text{F}_2(g) \xrightarrow{873 \text{ K}, 7 \text{ bar}} \mathbf{P}$ (1:5 ratio) $\mathbf{P} + \text{O}_2\text{F}_2 \xrightarrow{143 \text{ K}} \mathbf{Q} + \text{O}_2$ $\mathbf{Q} + \text{H}_2\text{O} \xrightarrow{\text{complete hydrolysis}} \mathbf{R} + \text{HF}$

(A) P has two lone pairs of electrons on the central atom.; (C) $\mathbf{Q}$ can act as a fluorinating agent.; (D) The molecular structure of $\mathbf{R}$ is trigonal pyramidal.

(B) $\mathbf{Q}$ has a perfect octahedral geometry.

JEE Advanced · 2026 · 17 May 2026 · Paper 2 · p-Block Elements

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Correct statement(s) about the compounds

P

Q

and

R

is(are)

Xe (g) + F_{2} (g) 873 K, 7 bar P

(1:5 ratio)

P + O_{2} F_{2} 143 K Q + O_{2}

Q + H_{2} O complete hydrolysis R + HF

(A)P has two lone pairs of electrons on the central atom.✓ Correct
(B) $Q$ has a perfect octahedral geometry.
(C) $Q$ can act as a fluorinating agent.✓ Correct
(D)The molecular structure of $R$ is trigonal pyramidal.✓ Correct

Answer: (A), (C), (D)

Solution

From the reactions:

$P = XeF_{4}$ (formed from 1:5 ratio of Xe:F₂)
$Q = XeF_{6}$ (oxidation of XeF₄)
$R = XeO_{3}$ (complete hydrolysis of XeF₆)

(A) Correct: XeF₄ has square planar geometry with 2 lone pairs on Xe.

(B) Incorrect: XeF₆ has distorted octahedral geometry (not perfect) due to one lone pair on Xe.

(C) Correct: XeF₆ is a strong fluorinating agent and can transfer fluorine atoms to other species.

(D) Correct: XeO₃ has trigonal pyramidal structure with one lone pair on Xe.

Therefore, options (A), (C), and (D) are correct.

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JEE Advanced · 2026 · 17 May 2026 · Paper 2 · p-Block Elements

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