One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV-diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.
LIST-I (P) In process I (Q) In process II (R) In process III (S) In process IV
LIST-II (1) Work done by the gas is zero (2) Temperature of the gas remains unchanged (3) No heat is exchanged between the gas and its surroundings (4) Work done by the gas is 6P0V0
(A)P→4;Q→3;R→1;S→2
(B)P→1;Q→3;R→2;S→4
(C)P→3;Q→4;R→1;S→2✓ Correct
(D)P→3;Q→4;R→2;S→1
Answer: (C)
Solution
From the PV diagram: Process I is adiabatic (steep curve, no heat exchange, Q=0) → P→3. Process II is isobaric (constant pressure, work W=PΔV=6P0V0) → Q→4. Process III is isochoric (constant volume, no work done) → R→1. Process IV is isothermal (constant temperature) → S→2. This matches option (C).
JEE Advanced · 2018 · 20 May 2018 · Paper 2 · Single correct option