Let and be functions defined by
(i) ,
(ii) , where the inverse trigonometric function assumes values in ,
(iii) , where, for denotes the greatest integer less than or equal to ,
(iv) .
The correct option is:
(i) ,
(ii) , where the inverse trigonometric function assumes values in ,
(iii) , where, for denotes the greatest integer less than or equal to ,
(iv) .
| LIST-I | LIST-II | ||
|---|---|---|---|
| P. | The function is | 1. | NOT continuous at |
| Q. | The function is | 2. | continuous at and NOT differentiable at |
| R. | The function is | 3. | differentiable at and its derivative is NOT continuous at |
| S. | The function is | 4. | differentiable at and its derivative is continuous at |
The correct option is:
- (A)
- (B)
- (C)
- (D)✓ Correct
Answer: (D)
Solution
****: Continuous at (both limits and value are 0). RHD = 1, LHD = -1, so not differentiable. P → 2
****: LHL = , RHL = , . Not continuous. Q → 1
****: Both LHL and RHL at are 0, and . Continuous. Both LHD and RHD are 0, so differentiable. The derivative is 0 in a neighborhood of 0, so the derivative is continuous. R → 4
****: Standard result: is continuous and differentiable at , but is not continuous at . S → 3
****: LHL = , RHL = , . Not continuous. Q → 1
****: Both LHL and RHL at are 0, and . Continuous. Both LHD and RHD are 0, so differentiable. The derivative is 0 in a neighborhood of 0, so the derivative is continuous. R → 4
****: Standard result: is continuous and differentiable at , but is not continuous at . S → 3
JEE Advanced · 2018 · 20 May 2018 · Paper 2 · Single correct option