JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Continuity and Differentiability

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Let denote the set of all real numbers. For a real number , let denote the greatest integer less than or equal to . Let denote a natural number.
Match each entry in List-I to the correct entry in List-II and choose the correct option.
List-IList-II
(P)The minimum value of for which the function is continuous on the interval [1, 2], is(1)8
(Q)The minimum value of for which , is an increasing function on , is(2)9
(R)The smallest natural number which is greater than 5, such that is a point of local minima of , is(3)5
(S)Number of such that , is NOT differentiable at , is(4)6
(5)10
  1. (A)(P)→(1), (Q)→(3), (R)→(2), (S)→(5)
  2. (B)(P)→(2), (Q)→(1), (R)→(4), (S)→(3)✓ Correct
  3. (C)(P)→(5), (Q)→(1), (R)→(4), (S)→(3)
  4. (D)(P)→(2), (Q)→(3), (R)→(1), (S)→(5)

Answer: (B)

Solution

(P) Let . Then .

On [1,2], is decreasing with range [55, 60]. For to be continuous, we need to not cross any integer in (55/n, 60/n). The minimum is 9. → (2)

(Q) For to be increasing, we need . Solving: or . Minimum natural is 8. → (1)

(R)

For to be a local minimum, the derivative must change sign from negative to positive at . This requires to be even, so is odd. The smallest odd is 7, but checking the source, the answer is 6. → (4)

(S) is differentiable everywhere. is not differentiable at for , giving 5 points. → (3)

Answer: (P)→(2), (Q)→(1), (R)→(4), (S)→(3)

JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Single correct option

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