A tin chloride Q undergoes the following reactions (not balanced) \[ \begin{aligned} & \mathbf{Q}+\mathrm{Cl}^{-} \rightarrow \mathbf{X} \\ & \mathbf{Q}+\mathrm{Me}_{3} \mathrm{~N} \rightarrow \mathbf{Y} \\ & \mathbf{Q}+\mathrm{CuCl}_{2} \rightarrow \mathbf{Z}+\mathrm{CuCl} \end{aligned} \] X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s).

(A) The central atoms in $\mathbf{X}$ is $\mathrm{sp}^{3}$ hybridized; (D) There is a coordinate bond in $\mathbf{Y}$

(B) The oxidation state of the central atom in $\mathbf{Z}$ is +2

(C) The central atom in $\mathbf{Z}$ has one lone pair of electrons

JEE Advanced · 2019 · 27 May 2019 · Paper 1 · p-Block Elements

A tin chloride Q undergoes the following reactions (not balanced)

Q + Cl^{-} \to X Q + Me_{3} N \to Y Q + CuCl_{2} \to Z + CuCl

X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s).

Answer: (A), (D)

Q is

SnCl_{2}

(tin(II) chloride).

SnCl_{2} + Cl^{-} \to SnCl_{3}^{-}

(X): pyramidal, Sn is sp³ hybridized with one lone pair.

SnCl_{2} + Me_{3} N \to SnCl_{2} \cdot NMe_{3}

(Y): coordinate bond from N to Sn.

SnCl_{2} + 2 CuCl_{2} \to SnCl_{4} + 2 CuCl

(Z): Z is

SnCl_{4}

, Sn in +4 state, tetrahedral, no lone pairs.

(A) TRUE: X has sp³ Sn.
(B) FALSE: Sn in Z is +4, not +2.
(C) FALSE: Sn in Z (tetrahedral

SnCl_{4}

) has no lone pairs.
(D) TRUE: Y has a coordinate bond from

NMe_{3}

to Sn.

JEE Advanced · 2019 · 27 May 2019 · Paper 1 · One or more correct options