As shown schematically in the figure, two vessels contain water solutions (at temperature T) of potassium permanganate (KMnO4) of different concentrations n1 and n2(n1>n2) molecules per unit volume with Δn=(n1−n2)≪n1. When they are connected by a tube of small length ℓ and cross-sectional area S,KMnO4 starts to diffuse from the left to the right vessel through the tube. Consider the collection of molecules to behave as dilute ideal gases and the difference in their partial pressure in the two vessels causing the diffusion. The speed v of the molecules is limited by the viscous force - β v on each molecule, where β is a constant. Neglecting all terms of the order (Δn)2, which of the following is/are correct? (kB is the Boltzmann constant)-
(A)the force causing the molecules to move across the tube is △nkBTS✓ Correct
(B)force balance implies n1βvℓ=ΔnkBT✓ Correct
(C)total number of molecules going across the tube per sec is (ℓΔn)(βkBT)S✓ Correct
(D)rate of molecules getting transferred through the tube does not change with time
Answer: (A), (B), (C)
Solution
Pressure difference: Δp = (n₁ - n₂)k_B T = Δn k_B T. Force on cross-section: F = Δp·S = Δn k_B T S ✓. For force balance, the pressure force equals the total viscous drag on all molecules in the tube: Δn k_B T S = (n₁ ℓ S)βv, giving n₁βvℓ = Δn k_B T ✓. Number flux = n₁vS. Using v = Δn k_B T/(n₁βℓ): flux = (Δn/ℓ)(k_B T/β)S ✓. As diffusion proceeds, Δn decreases with time, so the rate changes (D is incorrect).
JEE Advanced · 2020 · 27 Sep 2020 · Paper 1 · One or more correct options