The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by -character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below :
For the following reaction
the correct statement is
For the following reaction
the correct statement is
- (A)Initiation step is exothermic with
- (B)Propagation step involving formation is exothermic with
- (C)Propagation step involving formation is endothermic with
- (D)The reaction is exothermic with .✓ Correct
Answer: (D)
Solution
Calculate for the overall reaction using bond energies. Bonds broken: (+105 kcal/mol) and (+58 kcal/mol). Bonds formed: (−85 kcal/mol) and (−103 kcal/mol). kcal/mol. The reaction is exothermic. (A) Initiation () is endothermic (+58). (B) Propagation forming () has kcal/mol (endothermic). (C) Propagation forming () has kcal/mol (exothermic). Only (D) is correct.
JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Single correct option