The pair(s) of complexes wherein both exhibit tetrahedral geometry is(are) (Note: py = pyridine Given: Atomic numbers of Fe,Co,Ni and Cu are 26, 27, 28 and 29, respectively)
(A)[FeCl4]−and [Fe(CO)4]2−✓ Correct
(B)[Co(CO)4]−and [CoCl4]2−✓ Correct
(C)[Ni(CO)4] and [Ni(CN)4]2−
(D)[Cu(py)4]+and [Cu(CN)4]3−✓ Correct
Answer: (A), (B), (D)
Solution
Tetrahedral geometry occurs with weak-field ligands or when the d-electron configuration favors it. (A) [FeCl4]−: Fe³⁺ (d⁵) with weak-field Cl⁻ → tetrahedral. [Fe(CO)4]2−: Fe²⁻ (d¹⁰) → tetrahedral. (B) [Co(CO)4]−: Co⁻ (d¹⁰) → tetrahedral. [CoCl4]2−: Co²⁺ (d⁷) with weak-field Cl⁻ → tetrahedral. (C) [Ni(CO)4]: Ni⁰ (d¹⁰) → tetrahedral. [Ni(CN)4]2−: Ni²⁺ (d⁸) with strong-field CN⁻ → square planar (dsp² hybridization). (D) [Cu(py)4]+: Cu⁺ (d¹⁰) → tetrahedral. [Cu(CN)4]3−: Cu⁺ (d¹⁰) → tetrahedral. Options (A), (B), and (D) have both complexes tetrahedral.
JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · One or more correct options