The total number of all possible isomers for the square planar complex with formula $\mathrm{K}[\mathrm{M}(\mathrm{NCS})(\mathrm{NO}_{2})($ gly $)$] is ____ ( $\mathrm{M}=$ metal ion and gly $=\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{COO}^{-}$)

JEE Advanced · 2026 · 17 May 2026 · Paper 1 · Coordination Compounds

The total number of all possible isomers for the square planar complex with formula

K [M (NCS) (NO_{2}) (

gly

)

] is ____
(

M =

metal ion and gly

= NH_{2} CH_{2} COO^{-}

)

Answer: 8

Solution

For a square planar complex

[M (NCS) (NO_{2}) (gly)]^{-}

NCS can bind through N (thiocyanato) or S (isothiocyanato) — 2 linkage isomers
NO₂ can bind through N (nitro) or O (nitrito) — 2 linkage isomers
gly is a bidentate ligand (chelating)

For each combination of linkage isomers, there are geometrical isomers due to the square planar arrangement.

Total linkage isomer combinations: 2 × 2 = 4

For each linkage isomer, there are 2 geometrical isomers (cis/trans arrangements).

Total isomers = 4 × 2 = 8

JEE Advanced · 2026 · 17 May 2026 · Paper 1 · Numerical answer

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