Consider the given data with frequency distribution
Match each entry in List-I to the correct entries in List-II.
List-I
(P) The mean of the above data is
(Q) The median of the above data is
(R) The mean deviation about the mean of the above data is
(S) The mean deviation about the median of the above data is
List-II
(1) 2.5
(2) 5
(3) 6
(4) 2.7
(5) 2.4
The correct option is :
| 3 | 8 | 11 | 10 | 5 | 4 | |
|---|---|---|---|---|---|---|
| 5 | 2 | 3 | 2 | 4 | 4 |
Match each entry in List-I to the correct entries in List-II.
List-I
(P) The mean of the above data is
(Q) The median of the above data is
(R) The mean deviation about the mean of the above data is
(S) The mean deviation about the median of the above data is
List-II
(1) 2.5
(2) 5
(3) 6
(4) 2.7
(5) 2.4
The correct option is :
- (A)✓ Correct
- (B)(P) → (3) (Q) → (2) (R) → (1) (S) → (5)
- (C)
- (D)
Answer: (A)
Solution
(P) Mean: . P → (3)
(Q) Median: With 20 observations, median is the average of 10th and 11th observations. Arranging in order: 3,3,3,3,3,4,4,4,4,5,5,5,5,8,8,10,10,11,11,11. The 10th observation is 5. Q → (2) [Actually the median should be 5, but checking cumulative frequency: positions 1-5 are value 3, positions 6-9 are value 4, positions 10-13 are value 5. So 10th position is value 5.]
(R) Mean deviation about mean:
R → (4)
(S) Mean deviation about median:
S → (5)
Answer: (A)
(Q) Median: With 20 observations, median is the average of 10th and 11th observations. Arranging in order: 3,3,3,3,3,4,4,4,4,5,5,5,5,8,8,10,10,11,11,11. The 10th observation is 5. Q → (2) [Actually the median should be 5, but checking cumulative frequency: positions 1-5 are value 3, positions 6-9 are value 4, positions 10-13 are value 5. So 10th position is value 5.]
(R) Mean deviation about mean:
R → (4)
(S) Mean deviation about median:
S → (5)
Answer: (A)
JEE Advanced · 2023 · 04 Jun 2023 · Paper 1 · Single correct option