Question

Consider the following frequency distribution :

| Value | 4 | 5 | 8 | 9 | 6 | 12 | 11 |
|-------|---|---|---|---|---|----|----|
| Frequency | 5 | $f_{1}$ | $f_{2}$ | 2 | 1 | 1 | 3 |

Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6. For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma^{2}$ denote the variance.
Match each entry in List-I to the correct entry in List-II and choose the correct option.

| | List-I | | List-II |
|---|--------|---|--------|
| (P) | $7 f_{1}+9 f_{2}$ is equal to | (1) | 146 |
| (Q) | $19 \alpha$ is equal to | (2) | 47 |
| (R) | $19 \beta$ is equal to | (3) | 48 |
| (S) | $19 \sigma^{2}$ is equal to | (4) | 145 |
| | | (5) | 55 |

Accepted Answer

(C) (P)→(5), (Q)→(3), (R)→(2), (S)→(1)

Answer

(A) (P)→(5), (Q)→(3), (R)→(2), (S)→(4)

Answer

(B) (P)→(5), (Q)→(2), (R)→(3), (S)→(1)

Answer

(D) (P)→(3), (Q)→(2), (R)→(5), (S)→(4)

JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Statistics

Solution

More JEE Advanced questions on Statistics

	List-I		List-II
(P)	$7 f_{1} + 9 f_{2}$ is equal to	(1)	146
(Q)	$19 α$ is equal to	(2)	47
(R)	$19 β$ is equal to	(3)	48
(S)	$19 σ^{2}$ is equal to	(4)	145
		(5)	55