The complex(es), which can exhibit the type of isomerism shown by $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Br}_{2}\right]$, is(are) \[ \begin{aligned} & {\left[\mathrm{en}=\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\right]} \end{aligned} \]

(C) $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{4}\right]$; (D) $\left[\mathrm{Cr}(\mathrm{en})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)\left(\mathrm{SO}_{4}\right)\right]^{+}$

(A) $\left[\mathrm{Pt}(\mathrm{en})(\mathrm{SCN})_{2}\right]$

(B) $\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]$

JEE Advanced · 2023 · 04 Jun 2023 · Paper 2 · Coordination Compounds

WhatsApp Email

The complex(es), which can exhibit the type of isomerism shown by

[Pt (NH_{3})_{2} Br_{2}]

, is(are)

[en = H_{2} NCH_{2} CH_{2} NH_{2}]

(A) $[Pt (en) (SCN)_{2}]$
(B) $[Zn (NH_{3})_{2} Cl_{2}]$
(C) $[Pt (NH_{3})_{2} Cl_{4}]$ ✓ Correct
(D) $[Cr (en)_{2} (H_{2} O) (SO_{4})]^{+}$ ✓ Correct

Answer: (C), (D)

Solution

[Pt (NH_{3})_{2} Br_{2}]

is square planar (

dsp^{2}

hybridization) and exhibits cis-trans (geometrical) isomerism.

For a complex to show the same type of isomerism:

(A)

[Pt (en) (SCN)_{2}]

: Square planar, but en is a bidentate chelating ligand that occupies adjacent positions, so cis-trans isomerism is not possible.

(B)

[Zn (NH_{3})_{2} Cl_{2}]

: Tetrahedral geometry—no cis-trans isomerism in tetrahedral complexes.

(C)

[Pt (NH_{3})_{2} Cl_{4}]

: Octahedral geometry with two

NH_{3}

ligands—can exhibit cis-trans isomerism.

(D)

[Cr (en)_{2} (H_{2} O) (SO_{4})]^{+}

: Octahedral with two bidentate en ligands, one

H_{2} O

, and one

SO_{4}

—can exhibit cis-trans isomerism.

Therefore, (C) and (D) are correct.

JEE Advanced · 2023 · 04 Jun 2023 · Paper 2 · One or more correct options

Practise more: all JEE Advanced PYQs on Coordination Compounds →

JEE Advanced · 2023 · 04 Jun 2023 · Paper 2 · Coordination Compounds

Solution

More JEE Advanced questions on Coordination Compounds