JEE Advanced · 2024 · 26 May 2024 · Paper 1 · Geometrical Optics

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A light ray is incident on the surface of a sphere of refractive index at an angle of incidence . The ray partially refracts into the sphere with angle of refraction and then partly reflects from the back surface. The reflected ray then emerges out of the sphere after a partial refraction. The total angle of deviation of the emergent ray with respect to the incident ray is . Match the quantities mentioned in List-I with their values in List-II and choose the correct option.
List-I
(P)If and , then all the possible values of will be
(Q)If and , then all the possible values of will be
(R)If and , then all the possible values of will be
(S)If and , then all the possible values of will be
List-II
(1)30° and 0°
(2)60° and 0°
(3)45° and 0°
(4)150°
(5)0°
  1. (A)✓ Correct
  2. (B)
  3. (C)
  4. (D)

Answer: (A)

Solution

The total deviation is . For : . (P) With : gives , so (P→5). (Q) With : gives , so and (Q→2). (R) From and : , giving and (R→1). (S) With and : gives , and (S→4).

JEE Advanced · 2024 · 26 May 2024 · Paper 1 · Single correct option

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