JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Work, Power & Energy

A body of mass 1 kg moves along a straight line with a velocity

v = 2 x^{2}

. The work done by the body during displacement from

x = 0

to 5 m is ______ J.

(A)0
(B)250
(C)1250✓ Correct
(D)1000

Answer: (C)

Solution

By the work-energy theorem the work done equals the change in kinetic energy. With

v = 2 x^{2}

, the speed is

v_{i} = 0

x = 0

and

v_{f} = 2 (5)^{2} = 50 m/s

x = 5 m

. Hence

W = \frac{1}{2} m (v_{f}^{2} - v_{i}^{2}) = \frac{1}{2} (1) (5 0^{2} - 0) = 1250 J

JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Single correct option

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