JEE Main · 2026 · 02 Apr 2026 · Shift 2 · Work, Power & Energy

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A spherical ball of mass 2 kg falls from a height of 10 m and is brought to rest after penetrating 10 cm into sand. The average force exerted by sand on the ball is

____

(A)1980
(B)2020✓ Correct
(C)2000
(D)1000

Answer: (B)

Solution

Taking the ball from release to rest inside the sand, gravity acts over the whole drop plus penetration

(h + d)

while the sand resists over the depth

d

. By the work-energy theorem, with the ball starting and ending at rest,

m g (h + d) - F d = 0

. Hence

F = \frac{m g ( h + d )}{d} = \frac{2 \times 10 \times ( 10 + 0.1 )}{0.1} = \frac{20 \times 10.1}{0.1} = 2020 N

. The average force exerted by the sand is

2020

JEE Main · 2026 · 02 Apr 2026 · Shift 2 · Single correct option

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