The percentage of nitrogen in the yellow product (X) formed is _____ %. (Nearest Integer) (Given Molar mass in gmol−1 H: 1, C: 12, N: 14)
Answer: 21
Solution
Diazoaminobenzene, C6H5−N=N−NH−C6H5, on warming with excess aniline and a trace of aniline hydrochloride rearranges: the terminal −NH− linkage breaks and the diazonium end couples at the para position of an aniline ring. The yellow product is p-aminoazobenzene, C6H5−N=N−C6H4−NH2, of molecular formula C12H11N3.
Molar mass =12(12)+11(1)+3(14)=144+11+42=197gmol−1.
Mass percentage of nitrogen =1973×14×100=19742×100=21.3%.
The nitrogen content of the yellow product is 21%.