Statement-I : Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine.
Statement-II : Nitration of aniline with HNO₃/H₂SO₄ at 288 K produces m-nitroaniline in higher amount than o-nitroaniline ( pH adjusted).
In the light of the above statements, choose the correct answer from the options given below :
(A)Both Statement-I and Statement-II are true.
(B)Both Statement-I and Statement-II are false.
(C)Statement-I is true but Statement-II is false.
(D)Statement-I is false but Statement-II is true.✓ Correct
Answer: (D)
Solution
Heating benzamide with bromine in ethanolic sodium hydroxide is the Hofmann bromamide degradation, which removes the carbonyl carbon and gives aniline, Ph−NH2, not benzylamine, so Statement-I is false. When aniline is nitrated in the strongly acidic HNO3/H2SO4 mixture at 288K, it is largely protonated to the anilinium ion, whose −NH3+ group is deactivating and meta-directing, so an appreciable amount of m-nitroaniline is produced along with the ortho isomer, and Statement-II is taken as true. Statement-I is false but Statement-II is true.
JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Single correct option