JEE Main · 2004 · 24 Apr 2004 · Offline · Laws of Motion

Two masses

m_{1} = 5 kg

and

m_{2} = 4.8 kg

tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when lift free to move?
(

g = 9.8 m / s^{2}

)

(A) $0.2 m / s^{2}$ ✓ Correct
(B) $9.8 m / s^{2}$
(C) $5 m / s^{2}$
(D) $4.8 m / s^{2}$

Answer: (A)

Solution

With a light, frictionless pulley the two masses move together with one common acceleration

a = \frac{m _{1} - m _{2}}{m _{1} + m _{2}} g = \frac{5 - 4.8}{5 + 4.8} \times 9.8

. The factor

9.8

in the numerator and denominator cancels, leaving

a = 0.2

m/s

^{2}

JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option

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