Consider a car moving on a straight road with a speed of $100 \mathrm{~m} / \mathrm{s}$. The distance at which car can be stopped is $\left[\mu_{\mathrm{k}}=0.5\right]$

JEE Main · 2005 · 08 May 2005 · Offline · Laws of Motion

Consider a car moving on a straight road with a speed of

100 m / s

. The distance at which car can be stopped is

[μ_{k} = 0.5]

(A)800 m
(B)1000 m✓ Correct
(C)100 m
(D)400 m

Answer: (B)

Solution

Friction alone brings the car to rest, so by the work-energy theorem

μ_{k} m g s = \frac{1}{2} m u^{2}

. Hence

s = \frac{u ^{2}}{2 μ _{k} g} = \frac{10 0 ^{2}}{2 \times 0.5 \times 10} = 1000

JEE Main · 2005 · 08 May 2005 · Offline · Single correct option

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