Two Faraday of electricity is passed through a solution of . The mass of copper deposited at the cathode is: (at. mass of )
- (A)63.5 g✓ Correct
- (B)2 g
- (C)127 g
- (D)0 g
Answer: (A)
Solution
Copper plates out by , so each mole of copper needs two moles of electrons, i.e. two faradays. Passing exactly F therefore deposits one mole of copper, which is g.
JEE Main · 2015 · 04 Apr 2015 · Offline · Single correct option