This is a Wurtz-Fittig coupling: an aryl halide treated with sodium joins its two aromatic units through the carbons that carried the halogen. Here two tolyl fragments are stitched together, producing a dimethylbiphenyl. The product E is the biphenyl in which the two rings are bonded directly and each still bears its methyl group.
JEE Main · 2015 · 04 Apr 2015 · Offline · Single correct option