The color of $\mathrm{KMnO}_{4}$ is due to:

(B) $\mathrm{L} \rightarrow \mathrm{M}$ charge transfer transition

(C) $\sigma-\sigma^{*}$ transition

(D) $\mathrm{M} \rightarrow \mathrm{L}$ charge transfer transition

JEE Main · 2015 · 04 Apr 2015 · Offline · d and f Block Elements

The color of

KMnO_{4}

is due to:

(A) $d - d$ transition
(B) $L \to M$ charge transfer transition✓ Correct
(C) $σ - σ^{*}$ transition
(D) $M \to L$ charge transfer transition

Answer: (B)

Solution

The permanganate ion owes its deep purple not to

d - d

transitions -- manganese here is

Mn (VII)

, a

d^{0}

ion with no

d

electrons to promote. Instead the colour arises from a ligand-to-metal charge transfer, an electron jumping from the oxygen ligands onto the metal centre. Being fully allowed, this

L \to M

transition absorbs strongly and produces the intense colour.

JEE Main · 2015 · 04 Apr 2015 · Offline · Single correct option

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