The volume strength of $1 \mathrm{M} \mathrm{H}_{2} \mathrm{O}_{2}$ is : (Molar mass of $\mathrm{H}_{2} \mathrm{O}_{2}=34 \mathrm{~g} \mathrm{mol}^{-1}$ )

JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Hydrogen

The volume strength of

1 M H_{2} O_{2}

is : (Molar mass of

H_{2} O_{2} = 34 g mol^{- 1}

)

Answer: (C)

Volume strength is the volume of

O X_{2}

at STP released by one volume of solution. From

2 H X_{2} O X_{2} - > 2 H X_{2} O + O X_{2}

, one mole of

H X_{2} O X_{2}

yields half a mole of

O X_{2}

, that is

11.2

L. For a

1

M solution this is captured by the standard relation, volume strength

= 11.35 \times

molarity

= 11.35

JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option