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JEE Main · 2020 · 06 Sep 2020 · Shift 1 · General Organic Chemistry

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Which of the following compounds shows geometrical isomerism?
  1. (A)2 - methylpent 2 - ene
  2. (B)4 - methylpent 2 - ene✓ Correct
  3. (C)4 - methylpent - 1 - ene
  4. (D)2 - methylpent -1 - ene

Answer: (B)

Solution

Geometrical isomerism needs a carbon-carbon double bond on which each doubly bonded carbon carries two different groups, so that distinct cis and trans arrangements are possible. In 4-methylpent-2-ene, , one alkene carbon bears and while the other bears and the isobutyl group, so the two are distinguishable and cis-trans forms exist. The other candidates have either a terminal double bond or two identical groups on one alkene carbon, which rules out geometrical isomerism; only 4-methylpent-2-ene shows it.

JEE Main · 2020 · 06 Sep 2020 · Shift 1 · Single correct option

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