According to the following diagram, A reduces $\mathrm{BO}_{2}$ when the temperature is:

(D) $>1200^{\circ} \mathrm{C}$ but $<1400^{\circ} \mathrm{C}$

JEE Main · 2020 · 09 Jan 2020 · Shift 1 · General Principles and Processes of Isolation of Metals

According to the following diagram, A reduces

BO_{2}

when the temperature is:

Answer: (A)

In an Ellingham diagram a metal reduces another metal's oxide only when its own oxide line lies lower, so the overall

Δ G

is negative. For A to reduce

B O_{2}

, the

A O_{2}

line must sit below the

B O_{2}

line, and on the diagram given this happens only above

140 0^{\circ} C

, where the formation of

A O_{2}

becomes the more favourable of the two.

JEE Main · 2020 · 09 Jan 2020 · Shift 1 · Single correct option