JEE Main · 2021 · 01 Sep 2021 · Shift 2 · States of Matter

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An empty LPG cylinder weighs 14.8 kg . When full, it weighs 29.0 kg and shows a pressure of 3.47 atm . In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg . The final pressure inside of the cylinder is ____ atm. (Nearest integer)
(Assume LPG to be an ideal gas)

Answer: 2

Solution

The gas present when full is

29.0 - 14.8 = 14.2 kg

and the gas remaining is

23.0 - 14.8 = 8.2 kg

. Treating the contents as an ideal gas at fixed temperature and volume, pressure is proportional to the mass present, so

P_{2} = P_{1} \frac{m _{2}}{m _{1}} = 3.47 \times \frac{8.2}{14.2} = 2.00 atm

. The final pressure is

2 atm

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Integer answer

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