JEE Main · 2021 · 26 Feb 2021 · Shift 1 · Laws of Motion

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A person standing on a balance inside a stationary lift measures 60 kg . The weight of that person if the lift descends with uniform downward acceleration of

1.8 m / s^{2}

will be ____

N . [g = 10 m / s^{2}]

Answer: 492

Solution

The apparent weight when the lift accelerates downward is given by

W^{'} = m (g - a)

, where

m = 60

kg,

g = 10

m/s², and

a = 1.8

m/s². Therefore,

W^{'} = 60 (10 - 1.8) = 60 \times 8.2 = 492

JEE Main · 2021 · 26 Feb 2021 · Shift 1 · Integer answer

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