The oxide that gives $\mathrm{H}_{2} \mathrm{O}_{2}$ most readily on treatment with $\mathrm{H}_{2} \mathrm{O}$ is :

(A) $\mathrm{Na}_{2} \mathrm{O}_{2}$

(B) $\mathrm{BaO}_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}$

JEE Main · 2021 · 27 Aug 2021 · Shift 2 · Hydrogen

The oxide that gives

H_{2} O_{2}

most readily on treatment with

H_{2} O

is :

Answer: (A)

Sodium peroxide (

Na_{2} O_{2}

) reacts directly with water to give hydrogen peroxide:

Na_{2} O_{2} + 2 H_{2} O ⟶ 2 NaOH + H_{2} O_{2}

. Barium peroxide hydrate requires evaporation, while

PbO_{2}

and

SnO_{2}

form hydroxides instead. Hence (A) is correct.

JEE Main · 2021 · 27 Aug 2021 · Shift 2 · Single correct option