Let a circle C:(x−h)2+(y−k)2=r2,k>0, touch the x-axis at (1,0). If the line x+y=0 intersects the circle C at P and Q such that the length of the chord PQ is 2, then the value of h+k+r is equal to ____.
Answer: 7
Solution
Since the circle touches the x-axis at (1,0), we have h=1 and k=r (the center is at (1,r) with radius r).
The perpendicular distance from center (1,r) to the line x+y=0 is:
d=2∣1+r∣=21+r
Using the chord-distance formula with chord length PQ=2:
r2=d2+12=2(1+r)2+1
2r2=(1+r)2+2=1+2r+r2+2
r2−2r−3=0⇒(r−3)(r+1)=0
Since r>0, we have r=3.
Therefore, h+k+r=1+3+3=7.
JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Integer answer