Match List-I with List-II
List-I:
(A) Concentration of gold ore
(B) Leaching of alumina
(C) Froth stabiliser
(D) Blister copper
List-II:
(I) Aniline
(II) NaOH
(III)
(IV) NaCN
Choose the correct answer from the options given below.
List-I:
(A) Concentration of gold ore
(B) Leaching of alumina
(C) Froth stabiliser
(D) Blister copper
List-II:
(I) Aniline
(II) NaOH
(III)
(IV) NaCN
Choose the correct answer from the options given below.
- (A)(A) - (IV), (B) - (III), (C) - (II), (D) - (I)
- (B)(A) - (IV), (B) - (II), (C) - (I), (D) - (III)✓ Correct
- (C)(A) - (III), (B) - (II), (C) - (I), (D) - (IV)
- (D)(A) - (II), (B) - (IV), (C) - (III), (D) - (I)
Answer: (B)
Solution
Matching metallurgical processes:
Therefore: (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- Gold ore is concentrated by cyanidation using NaCN (Mac Arthur-Forrest process)
- Leaching of alumina from bauxite is done using NaOH (Bayer's process)
- Froth stabiliser in froth floatation process is aniline or cresols
- Blister copper has condensed on its surface (from roasting of copper pyrites)
Therefore: (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Single correct option