Match List-I with List-II List-I: (A) Spontaneous process (B) Process with $\Delta \mathrm{P}=0$, $\Delta \mathrm{T}=0$ (C) $\Delta \mathrm{H}_{\text{reaction}}$ (D) Exothermic process List-II: (I) $\Delta \mathrm{H}<0$ (II) $\Delta \mathrm{G}_{\mathrm{T}, \mathrm{P}}<0$ (III) Isothermal and isobaric process (IV) [Bond energies of molecules in reactants] - [Bond energies of product molecules] Choose the correct answer from the options given below:

(B) (A) - (II), (B) - (III), (C) - (IV), (D) - (I)

(A) (A) - (III), (B) - (II), (C) - (IV), (D) - (I)

(C) (A) - (II), (B) - (III), (C) - (I), (D) - (IV)

(D) (A) - (II), (B) - (I), (C) - (III), (D) - (IV)

JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Chemical Thermodynamics

Match List-I with List-II

List-I:
(A) Spontaneous process
(B) Process with

Δ P = 0

Δ T = 0

(C)

Δ H_{reaction}

(D) Exothermic process

List-II:
(I)

Δ H < 0

(II)

Δ G_{T, P} < 0

(III) Isothermal and isobaric process
(IV) [Bond energies of molecules in reactants] - [Bond energies of product molecules]

Choose the correct answer from the options given below:

(A)(A) - (III), (B) - (II), (C) - (IV), (D) - (I)
(B)(A) - (II), (B) - (III), (C) - (IV), (D) - (I)✓ Correct
(C)(A) - (II), (B) - (III), (C) - (I), (D) - (IV)
(D)(A) - (II), (B) - (I), (C) - (III), (D) - (IV)

Answer: (B)

Solution

Matching thermodynamic concepts:

Spontaneous process: $Δ G_{T, P} < 0$ (criterion for spontaneity)
$Δ P = 0$ (isobaric), $Δ T = 0$ (isothermal) → Isothermal and isobaric process
$Δ H_{reaction}$ = (Sum of bond energies of reactants) - (Sum of bond energies of products)
Exothermic process: $Δ H < 0$ (heat released)

Therefore: (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Single correct option

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JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Chemical Thermodynamics

Solution

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