Given below are two statements :
Statement I : According to the Ellingham diagram, any metal oxide with higher is more stable than the one with lower .
Statement II : The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the oxide of a metal placed higher in the diagram.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I : According to the Ellingham diagram, any metal oxide with higher is more stable than the one with lower .
Statement II : The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the oxide of a metal placed higher in the diagram.
In the light of the above statements, choose the most appropriate answer from the options given below :
- (A)Both Statement I and Statement II are correct.
- (B)Both Statement I and Statement II are incorrect.
- (C)Statement I is correct but Statement II is incorrect.
- (D)Statement I is incorrect but Statement II is correct.✓ Correct
Answer: (D)
Solution
Statement I is incorrect: In the Ellingham diagram, a metal oxide with LOWER (more negative) ΔG° is MORE stable, not higher.
Statement II is correct: A metal whose oxide formation line lies lower in the Ellingham diagram (more negative ΔG°) can reduce the oxide of a metal whose line lies higher (less negative ΔG°). This is the thermodynamic basis for metallurgical reduction reactions.
Statement II is correct: A metal whose oxide formation line lies lower in the Ellingham diagram (more negative ΔG°) can reduce the oxide of a metal whose line lies higher (less negative ΔG°). This is the thermodynamic basis for metallurgical reduction reactions.
JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Single correct option